New scripts for the truck condition(As suggested)

There have been some discussion about the truck condition and how people would like to have it modified a little. Well I got good news for all of you that requested this because the scripts for the truck condition has been completely rewritten. I will try to explain the formula as well as I can but I´m not sure if i can be clear enough with this.

Here we go, first of all the biggest change is that now the truck wear is based on the age of the truck(The older the bigger the wear on condition) and the miles the truck has on it(Once again the more miles the more wear). Below there is 2 examples, 1 truck is old and has a lot of miles on it and the other one is nearly new.

Example 1:
A 2008 Kenworth T-2000 with 21,582 miles on it

Example 2:
A 1977 Kenworth K-100 with 986,349 miles on it

Below is the math on how the condition is calculated:
Base wear on all trucks is 0.0003 % / mile
(aa=A number that has been made up to get the correct figures for the calculation)

Example 1 :
21582(miles) / 100000(aa) = 0.21582
0.21582(previous answer) / 10000(aa) = 0,0000215(Basically this calculation is here just so that I don´t have to use "millions" in the previous calculation)
2008(Truck Year) / 1000(aa) = 2.008
10(aa) - 2.008(previous answer) = 7.992 (This calculation is used to make sure that the newer trucks get a smaller number)
7.992(previous answer) / 10000(aa) =0.0007992

Now we can count everything together here:
0,0000215(for miles) + 0.0007992(For truck year) + 0.0003(Base wear for all trucks) = 0.0011207 wear/mile
This means that on a 1000 mile trip, this trucks wear is 0.0011207 * 1000 = 1.1207%/1000miles

Example 2 :
986349(miles) / 100000(aa) = 9.86349
9.86349(previous answer) / 10000(aa) = 0,0009863(Basically this calculation is here just so that I don´t have to use "millions" in the previous calculation)
1977(Truck Year) / 1000(aa) = 1.977
10(aa) - 1.977(previous answer) = 8.023 (This calculation is used to make sure that the newer trucks get a smaller number)
8.023(previous answer) / 10000(aa) =0.0008023

Now we can count everything together here:
0,0009863(for miles) + 0.0008023(For truck year) + 0.0003(Base wear for all trucks) = 0.0020886 wear/mile
This means that on a 1000 mile trip, this trucks wear is 0.0020886 * 1000 = 2.0886%/1000miles

From the calculations above we can see that the T-2000 drops it´s condition 1.1207% for every 1000 miles you drive while the K-100 drops 2.0886% for every 1000 miles!.........I should have become a math professor

Anyways, I want everyone to remember that the logbooks have been modified due to this and therefore I would want everyone to pay attention to the logs and make sure you report if you get any errors.....

Happy trucking everyone